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For all x and y, [m](4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 )
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02 Feb 2021, 09:05
02 Feb 2021, 09:05
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92% (00:48) correct
8% (00:41) wrong based on 25 sessions
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For all x and y, \((4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?\)
(A) \(–4x^2 – 18xy – 16y^2\)
(B) \(–4x^2 + 6xy – 16y^2\)
(C) \(–4x^2 + 6xy – 8y^2\)
(D) \(4x^2 – 6xy + 16y^2\)
(E) \(12x^2 – 18xy – 8y^2\)
(A) \(–4x^2 – 18xy – 16y^2\)
(B) \(–4x^2 + 6xy – 16y^2\)
(C) \(–4x^2 + 6xy – 8y^2\)
(D) \(4x^2 – 6xy + 16y^2\)
(E) \(12x^2 – 18xy – 8y^2\)
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Re: For all x and y, [m](4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 )
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02 Feb 2021, 09:47
02 Feb 2021, 09:47
1
Carcass wrote:
For all x and y, \((4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) = ?\)
(A) \(–4x^2 – 18xy – 16y^2\)
(B) \(–4x^2 + 6xy – 16y^2\)
(C) \(–4x^2 + 6xy – 8y^2\)
(D) \(4x^2 – 6xy + 16y^2\)
(E) \(12x^2 – 18xy – 8y^2\)
(A) \(–4x^2 – 18xy – 16y^2\)
(B) \(–4x^2 + 6xy – 16y^2\)
(C) \(–4x^2 + 6xy – 8y^2\)
(D) \(4x^2 – 6xy + 16y^2\)
(E) \(12x^2 – 18xy – 8y^2\)
This is all about collecting like terms
(4x² – 6xy – 12y²) – (8x² – 12xy + 4y²) = ??
4x² - 8x² = -4x²
–6xy - (–12xy) = 6xy (aka +6xy)
–12y² - 4y² = -16y²
So, (4x² – 6xy – 12y²) – (8x² – 12xy + 4y²) = -4x² + 6xy -16y²
Answer: B
gmatclubot
Re: For all x and y, [m](4x^2 – 6xy – 12y^2 ) – (8x^2 – 12xy + 4y^2 ) [#permalink]
02 Feb 2021, 09:47
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