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A machine, working at a constant rate, manufactures 36 staplers in 28
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22 Jan 2021, 09:35
22 Jan 2021, 09:35
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Question Stats:
87% (01:06) correct
12% (01:21) wrong based on 24 sessions
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A machine, working at a constant rate, manufactures 36 staplers in 28 minutes. How many staplers does it make in 1 hr 45 min?
A. 125
B. 128
C. 135
D. 144
E. 150
Kudos for a correct solution.
A. 125
B. 128
C. 135
D. 144
E. 150
Kudos for a correct solution.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: A machine, working at a constant rate, manufactures 36 staplers in 28
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22 Jan 2021, 09:46
22 Jan 2021, 09:46
1
Carcass wrote:
A machine, working at a constant rate, manufactures 36 staplers in 28 minutes. How many staplers does it make in 1 hr 45 min?
A. 125
B. 128
C. 135
D. 144
E. 150
Kudos for a correct solution.
A. 125
B. 128
C. 135
D. 144
E. 150
Kudos for a correct solution.
We can solve this using equivalent ratios
We're comparing machine output (measured in # of staplers) with time (in minutes)
1 hr 45 min = 105 minutes
Let x = # of staplers that can be made in 105 minutes
We get: 36/28 = x/105
Cross multiply to get: (28)(x) = (36)(105)
Divide both sides by 28 to get: x = (36)(105)/(28)
To calculate this, it's useful to recognize that 105 = (7)(15) and 36 = (4)(9) and 28 = (4)(7)
So, we get: x = (4)(9)(7)(15)/(4)(7)
Simplify to get: x = (9)(15)
= 135
Answer: C
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Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
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Re: A machine, working at a constant rate, manufactures 36 staplers in 28
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02 Feb 2021, 23:25
02 Feb 2021, 23:25
M1 x T1 x W2 = M2 x T2 x W1
Where;
M = Men
T = Time
W = Work
Always assume the missing variable as 1 (Here M1 = M2 = 1)
So,
28 x W2 = 105 x 36
W2 = 135
Where;
M = Men
T = Time
W = Work
Always assume the missing variable as 1 (Here M1 = M2 = 1)
So,
28 x W2 = 105 x 36
W2 = 135
