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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
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B_{n} = (−1)^n × n + 3 for all integers n ≥ 1. What is the 9th term of
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03 Feb 2021, 09:25
03 Feb 2021, 09:25
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\(B_{n} = (−1)^n × n + 3\) for all integers n ≥ 1. What is the 9th term of the sequence?
(A) -9
(B) -6
(C) -1
(D) 6
(E) 9
(A) -9
(B) -6
(C) -1
(D) 6
(E) 9
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B_{n} = (1)^n × n + 3 for all integers n 1. What is the 9th term of
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03 Feb 2021, 09:55
03 Feb 2021, 09:55
1
\(B_{n} = (−1)^n*n + 3\)
To find the 9th term we will replace n with 9 in \(B_{n} = (−1)^n*n + 3\)
=> \(B_{9} = (−1)^9*9+ 3\) = -1 * 9 + 3 = -9 + 3 = -6
So, Answer will be B
Hope it helps!
Watch the following video to MASTER Sequence problems
To find the 9th term we will replace n with 9 in \(B_{n} = (−1)^n*n + 3\)
=> \(B_{9} = (−1)^9*9+ 3\) = -1 * 9 + 3 = -9 + 3 = -6
So, Answer will be B
Hope it helps!
Watch the following video to MASTER Sequence problems
Re: B_{n} = (1)^n × n + 3 for all integers n 1. What is the 9th term of
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16 Apr 2024, 06:16
16 Apr 2024, 06:16
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