Explanation

Solve this problem by applying the compound interest formula:
\(V=P(1+\frac{r}{100})^t\)

Since the principal P is the same in both cases, leave it out and just compare the rest:

Quantity A: \((1+\frac{r}{100})^t=(1+\frac{8}{100})^2= (1.08)^2 = 1.08 × 1.08 = 1.1664\)

Quantity B: \((1+\frac{r}{100})^t=(1+\frac{4}{100})^4= (1.04)^4 = 1.04×1.04×1.04×1.04 ≈ 1.1699\)

Quantity B is greater.