GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
For all integers
[#permalink]
10 Feb 2021, 10:23
10 Feb 2021, 10:23
1
Expert Reply
4
Bookmarks
00:00
Question Stats:
76% (00:50) correct
23% (00:55) wrong based on 170 sessions
Hide Show timer Statistics
For all integers \(a\) and \(b\), \(a \vartriangle b = ab + 2(a+b)\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\( \frac{1}{1 \vartriangle 2 }\) |
\((0 \vartriangle 1 )^ {-3}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
For all integers
[#permalink]
10 Feb 2021, 19:37
10 Feb 2021, 19:37
2
\(a \vartriangle b = ab + 2(a+b)\)
Qt A
\(1 \vartriangle 2\)
= 1*2 + 2(1+2)
= 2 + 6
= 8
Qt A = \(\frac{1}{8}\)
Qt B
\(0 \vartriangle 1\)
= 0*1 + 2(0+1)
= 2
Now, \((2)^ {-3}\)
= \(\frac{1}{8}\)
Qt A = Qt B
Answer C
Qt A
\(1 \vartriangle 2\)
= 1*2 + 2(1+2)
= 2 + 6
= 8
Qt A = \(\frac{1}{8}\)
Qt B
\(0 \vartriangle 1\)
= 0*1 + 2(0+1)
= 2
Now, \((2)^ {-3}\)
= \(\frac{1}{8}\)
Qt A = Qt B
Answer C
Re: For all integers
[#permalink]
24 Oct 2024, 02:45
24 Oct 2024, 02:45
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
