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At Medville Hospital, Drug Xis prescribed only for Condition
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18 May 2020, 05:56
18 May 2020, 05:56
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Question Stats:
39% (02:31) correct
60% (02:16) wrong based on 63 sessions
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At Medville Hospital, Drug X is prescribed only for Condition A and Condition B, which may occur simultaneously in the same patient. Last year, the department recorded the following statistics for prescriptions of Drug X.
Which of the following could be the number of Medville Hospital patients for whom Drug X was prescribed last year?
Indicate all such numbers.
A. 514
B. 967
C. 1,372
D. 2,198
E. 2,447
F. 3,149
#greprepclub At Medville Hospital, Drug Xis prescribed.jpg [ 34.38 KiB | Viewed 6106 times ]
Which of the following could be the number of Medville Hospital patients for whom Drug X was prescribed last year?
Indicate all such numbers.
A. 514
B. 967
C. 1,372
D. 2,198
E. 2,447
F. 3,149
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#greprepclub At Medville Hospital, Drug Xis prescribed.jpg [ 34.38 KiB | Viewed 6106 times ]
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Re: At Medville Hospital, Drug Xis prescribed only for Condition
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13 Feb 2021, 01:27
13 Feb 2021, 01:27
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nurakib wrote:
sukrut96 wrote:
Thus, the range is from 1,600 (least amount of people who could've suffered from condition A and B) to 2,600 (maximum amount of people).
How do you calculate the least value, why can't I say least value is 1000?
Because you already have a higher value than 1000. 1600 people with Condition B have been prescribed drug X.
so, it has to be between 1600 and 2600
Think it this way;
People with Condition A = 1000
People with Condition B = 1600
People with Both the Conditions A and B = 1000 (Max. Intersection) and only Condition B = 600
Total people with prescription = 1600
i.e. (1000) + 600
Maximum = Condition A and Condition B separately = 1000 + 1600 = 2600 ......... (Only Union, no Intersection)
General Discussion
Re: At Medville Hospital, Drug Xis prescribed only for Condition
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18 May 2020, 06:11
18 May 2020, 06:11
2
It is given that Medville Hospital prescribes the drug only for condition A and condition B, when both of them occur.
4,000 * 0.25 = 1,000 and 2,000 * 0.8 = 1,600,
Thus, the total number of patients who used the drug were, 2,600.
Thus, the range is from 1,600 (least amount of people who could've suffered from condition A and B) to 2,600 (maximum amount of people).
Hence, option D and E fit in this range.
4,000 * 0.25 = 1,000 and 2,000 * 0.8 = 1,600,
Thus, the total number of patients who used the drug were, 2,600.
Thus, the range is from 1,600 (least amount of people who could've suffered from condition A and B) to 2,600 (maximum amount of people).
Hence, option D and E fit in this range.
