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x=1−2y, and 5x+10y+z=5. What is the value of z?
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15 Feb 2021, 07:05
15 Feb 2021, 07:05
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x=1−2y, and 5x+10y+z=5. What is the value of z?
A. -5
B. 0
C. 5
D. 10
E. The answer cannot be determined from the data provided.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. -5
B. 0
C. 5
D. 10
E. The answer cannot be determined from the data provided.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
x=1−2y, and 5x+10y+z=5. What is the value of z?
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15 Feb 2021, 07:22
15 Feb 2021, 07:22
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Carcass wrote:
x=1−2y, and 5x+10y+z=5. What is the value of z?
A. -5
B. 0
C. 5
D. 10
E. The answer cannot be determined from the data provided.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. -5
B. 0
C. 5
D. 10
E. The answer cannot be determined from the data provided.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Given: x = 1 - 2y
Add 2y to both sides to get: x + 2y = 1
Given: 5x + 10y + z = 5
Notice that we have x + 2y "hiding" in this expression.
Rewrite the first two terms as follows: 5(x + 2y) + z = 5
Replace x + 2y with 1 to get: 5(1) + z = 5
Simplify: 5 + z = 5
Solve: z = 0
Answer: B
Cheers,
Brent
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: x=1−2y, and 5x+10y+z=5. What is the value of z?
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15 Feb 2021, 07:35
15 Feb 2021, 07:35
Carcass wrote:
x=1−2y, and 5x+10y+z=5. What is the value of z?
A. -5
B. 0
C. 5
D. 10
E. The answer cannot be determined from the data provided.
A. -5
B. 0
C. 5
D. 10
E. The answer cannot be determined from the data provided.
\(x = 1 - 2y\)
\(x + 2y = 1\)
Now, \(5x + 10y + z = 5\)
\(5(x + 2y) + z = 5\)
\(5(1) + z = 5\)
\(z = 5 - 5 = 0\)
Hence, option B
