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The preceding figure shows a regular hexagon. What is the value of x?
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18 Feb 2021, 04:14
18 Feb 2021, 04:14
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95% (00:27) correct
5% (00:10) wrong based on 20 sessions
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Show: :: OA
120
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Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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The preceding figure shows a regular hexagon. What is the value of x?
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18 Feb 2021, 06:33
18 Feb 2021, 06:33
1
Carcass wrote:
Attachment:
GRE exagon.jpg
The preceding figure shows a regular hexagon. What is the value of x?Show: :: OA
120
Each Interior Angle of any polygon = \(\frac{(n - 2)}{n}\) x \(180°\)
where, \(n\) = number of sides
Here, \(n = 6\)
So, \(x = \frac{(6 - 2)}{6}\) x \(180°\)
\(x = 120°\)
I would recommend to learn the angles of first 10 regular polygons;
Equilateral triangle = 60°
Square = 90°
Pentagon = 108°
Hexagon = 120°
Heptagon = 128.5°
Octagon = 135°
Nonagon = 140°
Decagon = 144°
Re: The preceding figure shows a regular hexagon. What is the value of x?
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18 Feb 2021, 07:43
18 Feb 2021, 07:43
1
Hi,
If you tend to forget the formulae, make sure you have a backup!!
Here, we know every figure with any number of sides will have exterior angle =360.
Divide 360 by the number of sides of the quadrilateral.
i.e. 360/6=60 degrees.
Now, a straight line has an angle of 180 degrees. Subtract this 180 with 60(Or whatever length you get after dividing)
180-60=120 degrees.
Hence x=120 degrees.
Hope this helps!
If you tend to forget the formulae, make sure you have a backup!!
Here, we know every figure with any number of sides will have exterior angle =360.
Divide 360 by the number of sides of the quadrilateral.
i.e. 360/6=60 degrees.
Now, a straight line has an angle of 180 degrees. Subtract this 180 with 60(Or whatever length you get after dividing)
180-60=120 degrees.
Hence x=120 degrees.
Hope this helps!
