GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
2^20/3^15
[#permalink]
21 Feb 2021, 10:25
21 Feb 2021, 10:25
Expert Reply
00:00
Question Stats:
97% (00:35) correct
2% (01:37) wrong based on 36 sessions
Hide Show timer Statistics
Quantity A |
Quantity B |
\(\frac{2^{20}}{3^{15}}\) |
\(\frac{16^5}{27^5 }\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
2^20/3^15
[#permalink]
21 Feb 2021, 10:37
21 Feb 2021, 10:37
Solution:
Qty A: \(\frac{2^2^0}{3^1^5}\)
Qty B: \(\frac{16^5}{27^5}\)
We know 16=\(2^4\) & 27=\(3^3\)
Thus, \(\frac{16^5}{27^5}\)=\(\frac{2^4^*^5}{3^3^*^5}\)=\(\frac{2^2^0}{3^1^5}\)
Hence, QTY A=QTY B
IMO C
Hope this helps!
Qty A: \(\frac{2^2^0}{3^1^5}\)
Qty B: \(\frac{16^5}{27^5}\)
We know 16=\(2^4\) & 27=\(3^3\)
Thus, \(\frac{16^5}{27^5}\)=\(\frac{2^4^*^5}{3^3^*^5}\)=\(\frac{2^2^0}{3^1^5}\)
Hence, QTY A=QTY B
IMO C
Hope this helps!
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
2^20/3^15
[#permalink]
21 Feb 2021, 12:13
21 Feb 2021, 12:13
1
Carcass wrote:
Quantity A |
Quantity B |
\(\frac{2^{20}}{3^{15}}\) |
\(\frac{16^5}{27^5 }\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Power of a Power law: \((b^x)^y=b^{xy}\)
Given:
Quantity A: \(\frac{2^{20}}{3^{15}}\)
Quantity B: \(\frac{16^5}{27^5 }\)
Rewrite \(16\) as \(2^4\) and rewrite \(27\) as \(3^3\) to get:
Quantity A: \(\frac{2^{20}}{3^{15}}\)
Quantity B: \(\frac{(2^4)^5}{(3^3)^5 }\)
Apply the Power of a Power law to get:
Quantity A: \(\frac{2^{20}}{3^{15}}\)
Quantity B: \(\frac{2^{20}}{3^{15}}\)
Answer: C
