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Re: If the 67 children residing on a certain street. 52 children enjo [#permalink]
can someone pls elaborate? seems confusing.

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Re: If the 67 children residing on a certain street. 52 children enjo [#permalink]
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Ashok2345 wrote:
Of the 67 children residing on a certain street. 52 children enjoy biking and 21 children enjoy roller skating. If all but 5 of the children enjoy biking or roller skating or both. How many of the children either biking or roller skating but not both skating and biking?

A)11
B)31
C)51
D)61
E)62

Posted from my mobile device


I think it's C!

Total students = \(67\)
Biking = \(52\)
Skating = \(21\)

The glitch: If all but 5 of the children enjoy biking or roller skating or both
That is 5 students like nothing

So, the Union of 2 sets = \(67 - 5 = 62\)

Union = Biking + Skating - Both
\(62 = 52 + 21 - x\)
\(x = 11\)

So, only Biking + only Skating = \(62 - 11 = 51\)
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Re: If the 67 children residing on a certain street. 52 children enjo [#permalink]
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KarunMendiratta
Thank You so much.
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Re: If the 67 children residing on a certain street. 52 children enjo [#permalink]
AjanthaJ wrote:
Thank You so much.


Anytime :thumbsup:
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Re: If the 67 children residing on a certain street. 52 children enjo [#permalink]
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