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Re: If the 67 children residing on a certain street. 52 children enjo [#permalink]
can someone pls elaborate? seems confusing.

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Re: If the 67 children residing on a certain street. 52 children enjo [#permalink]
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Ashok2345 wrote:
Of the 67 children residing on a certain street. 52 children enjoy biking and 21 children enjoy roller skating. If all but 5 of the children enjoy biking or roller skating or both. How many of the children either biking or roller skating but not both skating and biking?

A)11
B)31
C)51
D)61
E)62

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I think it's C!

Total students = \(67\)
Biking = \(52\)
Skating = \(21\)

The glitch: If all but 5 of the children enjoy biking or roller skating or both
That is 5 students like nothing

So, the Union of 2 sets = \(67 - 5 = 62\)

Union = Biking + Skating - Both
\(62 = 52 + 21 - x\)
\(x = 11\)

So, only Biking + only Skating = \(62 - 11 = 51\)
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Re: If the 67 children residing on a certain street. 52 children enjo [#permalink]
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KarunMendiratta
Thank You so much.
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Re: If the 67 children residing on a certain street. 52 children enjo [#permalink]
AjanthaJ wrote:
Thank You so much.


Anytime :thumbsup:
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Re: If the 67 children residing on a certain street. 52 children enjo [#permalink]
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