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100!/98!
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22 Feb 2021, 10:00
22 Feb 2021, 10:00
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Question Stats:
100% (00:21) correct
0% (00:00) wrong based on 22 sessions
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Quantity A |
Quantity B |
\(\frac{100!}{98!}\) |
\(99^2\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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100!/98!
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22 Feb 2021, 10:17
22 Feb 2021, 10:17
1
Carcass wrote:
Quantity A |
Quantity B |
\(\frac{100!}{98!}\) |
\(99^2\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Col. A: \(\frac{100!}{98!} = \frac{(100)(99)(98!)}{98!} = (100)(99)\)
Col. B: \(99^2 = (99)(99)\)
Col. A: \(100\)
Col. B: \(99\)
Col. A > Col. B
Hence, option A
