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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
A large tub is filled with 920 liters of water and 1,800 liters of
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24 Feb 2021, 07:00
24 Feb 2021, 07:00
Expert Reply
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Question Stats:
80% (01:15) correct
20% (02:16) wrong based on 15 sessions
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A large tub is filled with 920 liters of water and 1,800 liters of alcohol. If 40% of the alcohol evaporates, what percent of the remaining liquid is water?
A. 40%
B. 43%
C. 46%
D. 50%
E. 56%
A. 40%
B. 43%
C. 46%
D. 50%
E. 56%
Re: A large tub is filled with 920 liters of water and 1,800 liters of
[#permalink]
24 Feb 2021, 08:07
24 Feb 2021, 08:07
1
Remaining Alcohol after 40% of the alcohol evaporates will be = 1800 - 1800 * 0.4 = 1080
Water remains as it is, so the total remaining liquid in the tub is = 1080 + 920 = 2000
So, percentage of water is = (920 / 2000) * 100 = 46 %
Answer is C
Water remains as it is, so the total remaining liquid in the tub is = 1080 + 920 = 2000
So, percentage of water is = (920 / 2000) * 100 = 46 %
Answer is C
A large tub is filled with 920 liters of water and 1,800 liters of
[#permalink]
25 Feb 2024, 22:08
25 Feb 2024, 22:08
1
\(40\)% of alcohol = \(1800 \times \frac{40}{100}= 720\) liters
Alcohol that remains after evaporation is \(1800-720=1080\) liters
The amount of water available = \(920\) liters
Total amount of water and alcohol remaining = \(1080+920=2000\) liters
Percentage of water \(= \frac{920}{2000} \times 100 = 46\)%
The answer is C
Alcohol that remains after evaporation is \(1800-720=1080\) liters
The amount of water available = \(920\) liters
Total amount of water and alcohol remaining = \(1080+920=2000\) liters
Percentage of water \(= \frac{920}{2000} \times 100 = 46\)%
The answer is C
