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In a get together, every 3 guests used a bowl of soup between them,
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25 Feb 2021, 01:06
25 Feb 2021, 01:06
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In a get together, every 3 guests used a bowl of soup between them, every 2 guests used a bowl of rice between them and every 4 guests used a bowl of meat between them. There were altogether 91 bowls. How many guests were present at the get together?
A. 70
B. 72
C. 80
D. 84
E. None of the above
A. 70
B. 72
C. 80
D. 84
E. None of the above
Re: In a get together, every 3 guests used a bowl of soup between them,
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25 Feb 2021, 02:06
25 Feb 2021, 02:06
4
This is a divisibility problem. First, notice that the number of guests must be divisible by 2,3, and 4: no fractional bowls are allowed due to the problem's nature. We can thus immediately eliminate A & C.
Turning to the remaining answers, let's check B & D; the number of bowls consumed by the guests must equal 91 as given in the problem.
For B: 72/4 + 72/3 + 72/2 = 18 + 24 + 36 = 78 < 91
For D: 84 * (1/4+1/3+1/2) = 84*(13/12) = 7*13 = 91 ( I did this one differently to test my mental math.)
The answer is D.
Turning to the remaining answers, let's check B & D; the number of bowls consumed by the guests must equal 91 as given in the problem.
For B: 72/4 + 72/3 + 72/2 = 18 + 24 + 36 = 78 < 91
For D: 84 * (1/4+1/3+1/2) = 84*(13/12) = 7*13 = 91 ( I did this one differently to test my mental math.)
The answer is D.
Re: In a get together, every 3 guests used a bowl of soup between them,
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25 Feb 2021, 02:53
25 Feb 2021, 02:53
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S=3, R=2, M=4
for 12 people: 3*M+6*R+4*S = 13 bowls.
91/13 = 7.
7*12 = 84
for 12 people: 3*M+6*R+4*S = 13 bowls.
91/13 = 7.
7*12 = 84
