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What is the maximum possible area of a triangle with a side of length
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03 Mar 2021, 06:15
03 Mar 2021, 06:15
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What is the maximum possible area of a triangle with a side of length 7 units and another side of length 8 units?
A. 14 square units
B. 21 square units
C. 28 square units
D. 56 square units
E. 64 square units
A. 14 square units
B. 21 square units
C. 28 square units
D. 56 square units
E. 64 square units
Re: What is the maximum possible area of a triangle with a side of length
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03 Mar 2021, 08:25
03 Mar 2021, 08:25
1
In a triangle with 2 sides given, The largest possible area is formed if these two sides are perpendicular to each other and also the two smaller sides among the 3 sides of a triangle. Care should be taken that the three sides so obtained do not violate the triangle principle.
1) Sum of two sides of a triangle must be greater than the third side.
2) Each side should be more than the difference between the other two sides.
Area would then be \(1/2 * 7 * 8\) = \(7*4\) = \(28\)
C
1) Sum of two sides of a triangle must be greater than the third side.
2) Each side should be more than the difference between the other two sides.
Area would then be \(1/2 * 7 * 8\) = \(7*4\) = \(28\)
C
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What is the maximum possible area of a triangle with a side of length
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03 Mar 2021, 22:20
03 Mar 2021, 22:20
GeminiHeat wrote:
What is the maximum possible area of a triangle with a side of length 7 units and another side of length 8 units?
A. 14 square units
B. 21 square units
C. 28 square units
D. 56 square units
E. 64 square units
A. 14 square units
B. 21 square units
C. 28 square units
D. 56 square units
E. 64 square units
Right Triangle has the Maximum Area
So, let \(b\) and \(h\) be 7 and 8 only
Area = \(\frac{1}{2}(7)(8) = 28\)
Hence, option C
