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In a certain basket, there are 50 apples and 30 bananas. If the same n
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04 Mar 2021, 02:47
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In a certain basket, there are 50 apples and 30 bananas. If the same number of apples and bananas is removed, how many of each fruit would have to be removed for the resulting ratio of the new number of apples to the new number of bananas to equal 5:1?
Re: In a certain basket, there are 50 apples and 30 bananas. If the same n
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04 Mar 2021, 03:01
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Solution:
Solved this in 30 secs without writing anything.
Focus on the ratio 5:1, If you know how to g to the answer from this ratio, the question is pretty easy. The ratio basically means if we have 5 apples, then we have 1 banana. Using the option (I started from a mid range, this helps to know whether I need upper value or lower value) 15---> 15 apple=3 banana. This means the same number of fruits were not removed. 20-->20 apples=4 banana. OUT 25---> 25 Apples=5 Banana= Yes this means 25 apples and 25 bananas were removed.
Re: In a certain basket, there are 50 apples and 30 bananas. If the same n
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04 Mar 2021, 07:57
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Carcass wrote:
In a certain basket, there are 50 apples and 30 bananas. If the same number of apples and bananas is removed, how many of each fruit would have to be removed for the resulting ratio of the new number of apples to the new number of bananas to equal 5:1?
5 10 15 20 25
Kudos for the right answer and explanation
Let the number of fruit to be removed be \(x\) Then, \(\frac{(50 - x)}{(30 - x)} = \frac{5}{1}\) \((50 - x) = 5(30 - x)\) \(4x = 100\) \(x = 25\)
Hence, option E
gmatclubot
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