GeminiHeat wrote:
A cylinder has a surface area of \(360π\) and height of 3. What is the diameter of the cylinder’s circular base?
A. 12
B. 24
C. 36
D. 48
E. 60
T.S.A of Cylinder = \(2πr(H+r)\)
So, \(2πr(H+r) = 360π\)
\(r(H+r) = 180\)
\(r(3+r) = 180\) .............. [H = 3]
\(12(3+12) = 180\)
i.e. \(r=12\)
Then, Diameter\( = 2r = 24\)
Hence, option B