GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 17Live Online Classes with Top GRE Expert Rich Zwelling
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Tues/Thur Sept 7, 2026---Feb. 2, 2027, 1:00pm-3:00pm EST
Dec 14Live Online Classes with Top GRE Expert Michael Butville
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Mon/Wed Dec. 14, 2026---Feb. 22, 2027, 8:00pm-10:00pm EST
1/1+sqrt1/3
[#permalink]
06 Mar 2021, 02:43
06 Mar 2021, 02:43
Expert Reply
1
Bookmarks
00:00
Question Stats:
60% (00:47) correct
39% (01:06) wrong based on 46 sessions
Hide Show timer Statistics
Quantity A |
Quantity B |
\(\frac{1}{1+ \sqrt{\frac{1}{3}}}\) |
\(\frac{1}{1+ \sqrt{\frac{1}{4}}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
1/1+sqrt1/3
[#permalink]
06 Mar 2021, 02:53
06 Mar 2021, 02:53
1
Carcass wrote:
Quantity A |
Quantity B |
\(\frac{1}{1+ \sqrt{\frac{1}{3}}}\) |
\(\frac{1}{1+ \sqrt{\frac{1}{4}}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Col. A: \(\frac{\sqrt{3}}{{1 + \sqrt{3}}}\)
Col. B: \(\frac{\sqrt{4}}{{1 + \sqrt{4}}}\)
Cross-multiplying the denominators;
Col. A: \(\sqrt{3}(1+\sqrt{4})\)
Col. B: \(\sqrt{4}(1+\sqrt{3})\)
Col. A: \(\sqrt{3} + \sqrt{12}\)
Col. b: \(\sqrt{4} + \sqrt{12}\)
Subtracting \(\sqrt{12}\) from both the sides;
Col. A: \(\sqrt{3}\)
Col. B: \(\sqrt{4}\)
Hence, option B
Re: 1/1+sqrt1/3
[#permalink]
07 Mar 2021, 14:42
07 Mar 2021, 14:42
This one its preety easy...
Both which from A and B will take more from one?
1+ square root of .33
OR
1+ square root of .25?
Withour knowing how much is the square root of .33 and .25 clearly sqaure root of .25 will be smaller and hence, will take less from 1.
B
Both which from A and B will take more from one?
1+ square root of .33
OR
1+ square root of .25?
Withour knowing how much is the square root of .33 and .25 clearly sqaure root of .25 will be smaller and hence, will take less from 1.
B
