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When 26 is divided by K, the remainder is K-2, k >= 2 , k=?

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Lester
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When 26 is divided by K, the remainder is K-2, k >= 2 , k=? [#permalink] New post   Updated on: 15 Aug 2024, 12:33
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When 26 is divided by K, the remainder is K-2. K >= 2


Quantity A
Quantity B
Sum of all possible values of K
55



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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A

Originally posted by Lester on 09 Mar 2021, 21:08.
Last edited by Carcass on 15 Aug 2024, 12:33, edited 1 time in total.
Fixed OA
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KarunMendiratta
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Re: When 26 is divided by K, the remainder is K-2, k >= 2 , k=? [#permalink] New post   09 Mar 2021, 23:33
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Lester wrote:
When 26 is divided by K, the remainder is K-2. K >= 2


Quantity A
Quantity B
Sum of all possible values of K
55



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Any number \(N\) when divided by divisor \(x\) can be written as: \(N = xQ + Remainder\)

Here, \(26 = KQ + (K - 2)\)
i.e. \(26 + 2 = K (Q + 1)\)
\(K = \frac{28}{(Q + 1)}\)

When \(Q = 0\), \(K = 28\)
When \(Q = 1\), \(K = 14\)
When \(Q = 3\), \(K = 07\)
When \(Q = 6\), \(K = 04\)
When \(Q = 13\), \(K = 02\)
When \(Q = 27\), \(K = 01\)

Col. A: Sum of all possible values of k is \(56\)
Col. B: \(55\)

Hence, option A
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Re: When 26 is divided by K, the remainder is K-2, k >= 2 , k=? [#permalink] New post   10 Mar 2021, 02:52
thank you so much !
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Re: When 26 is divided by K, the remainder is K-2, k >= 2 , k=? [#permalink] New post   30 May 2021, 01:09
KarunMendiratta wrote:
Lester wrote:
When 26 is divided by K, the remainder is K-2. K >= 2


Quantity A
Quantity B
Sum of all possible values of K
55



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Any number \(N\) when divided by divisor \(x\) can be written as: \(N = xQ + Remainder\)

Here, \(26 = KQ + (K - 2)\)
i.e. \(26 + 2 = K (Q + 1)\)
\(K = \frac{28}{(Q + 1)}\)

When \(Q = 0\), \(K = 28\)
When \(Q = 1\), \(K = 14\)
When \(Q = 3\), \(K = 07\)
When \(Q = 13\), \(K = 04\)
When \(Q = 27\), \(K = 02\)

Col. A: Sum of all possible values of k is \(55\)
Col. B: \(55\)

Hence, option C


When \(Q = 13\), \(K = 02\)
When \(Q = 27\), \(K = 0\), Is not it sir?
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KarunMendiratta
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Re: When 26 is divided by K, the remainder is K-2, k >= 2 , k=? [#permalink] New post   30 May 2021, 01:32
kumarneupane4344 wrote:
KarunMendiratta wrote:
Lester wrote:
When 26 is divided by K, the remainder is K-2. K >= 2


Quantity A
Quantity B
Sum of all possible values of K
55



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Any number \(N\) when divided by divisor \(x\) can be written as: \(N = xQ + Remainder\)

Here, \(26 = KQ + (K - 2)\)
i.e. \(26 + 2 = K (Q + 1)\)
\(K = \frac{28}{(Q + 1)}\)

When \(Q = 0\), \(K = 28\)
When \(Q = 1\), \(K = 14\)
When \(Q = 3\), \(K = 07\)
When \(Q = 13\), \(K = 04\)
When \(Q = 27\), \(K = 02\)

Col. A: Sum of all possible values of k is \(55\)
Col. B: \(55\)

Hence, option C


When \(Q = 13\), \(K = 02\)
When \(Q = 27\), \(K = 0\), Is not it sir?


Correct Sir, I have made the necessary changes.
The OA must be A
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YoshS
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Re: When 26 is divided by K, the remainder is K-2, k >= 2 , k=? [#permalink] New post   15 Aug 2024, 11:24
KarunMendiratta wrote:
Lester wrote:
When 26 is divided by K, the remainder is K-2. K >= 2


Quantity A
Quantity B
Sum of all possible values of K
55



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Any number \(N\) when divided by divisor \(x\) can be written as: \(N = xQ + Remainder\)

Here, \(26 = KQ + (K - 2)\)
i.e. \(26 + 2 = K (Q + 1)\)
\(K = \frac{28}{(Q + 1)}\)

When \(Q = 0\), \(K = 28\)
When \(Q = 1\), \(K = 14\)
When \(Q = 3\), \(K = 07\)
When \(Q = 6\), \(K = 04\)
When \(Q = 13\), \(K = 02\)
When \(Q = 27\), \(K = 01\)

Col. A: Sum of all possible values of k is \(56\)
Col. B: \(55\)

Hence, option A
Question says K>=2 when q=27 then k=1 this value of k shall not be added to the sum as that fails the condition that k>=2. The sum then of all the possible values comes to be 55 hence, the answer should be C
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gmatclubot
Re: When 26 is divided by K, the remainder is K-2, k >= 2 , k=? [#permalink]
15 Aug 2024, 11:24
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