Lester wrote:
In 1990 the rainfall in City X during April was 3 times the average monthly rainfall for the other 11 months. If the total rainfall for the year was 35 inches, what was the rainfall, in inches, during April ?
(A) 2.5
(B) 4
(C)6
(D)7.5
(E)9.5
\(A = 3\frac{(x_1 + x_2 + ......... + x_{11})}{11}\)
\((x_1 + x_2 + ......... + x_{11}) = \frac{11A}{3}\)
Now, \(A + (x_1 + x_2 + ......... + x_{11}) = 35\)
i.e. \(A + \frac{11A}{3} = 35\)
\(\frac{14A}{3} = 35\)
\(A = \frac{(35)(3)}{(14)} = \frac{15}{2} = 7.5\)
Hence, option D