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In company X, no employee is both a technician and an accoun
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10 Mar 2019, 10:45
10 Mar 2019, 10:45
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In company X, no employee is both a technician and an accountant. Also, in company X, \(\frac{2}{5}\) of the employees are technicians, and \(\frac{5}{16}\) of the remaining employees are accountants. What fraction of the total number of employees at company X are neither technicians nor accountants?
A. \(\frac{23}{80}\)
B. \(\frac{33}{80}\)
C. \(\frac{3}{7}\)
D. \(\frac{47}{80}\)
E. \(\frac{57}{80}\)
A. \(\frac{23}{80}\)
B. \(\frac{33}{80}\)
C. \(\frac{3}{7}\)
D. \(\frac{47}{80}\)
E. \(\frac{57}{80}\)
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Re: In company X, no employee is both a technician and an accoun
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12 Mar 2019, 06:45
12 Mar 2019, 06:45
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2/5 are technicians, and 5/16 of the remaining 3/5 are accountants - that's 3/5*5/16=3/16.
We'll find the common denominator of both fractions: 2/5 = 32/80, 5/16 = 25/80. so technicians plus accountants are 25+32=57/80. those that are neither are 80-57=23/80. A.
We'll find the common denominator of both fractions: 2/5 = 32/80, 5/16 = 25/80. so technicians plus accountants are 25+32=57/80. those that are neither are 80-57=23/80. A.
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Re: In company X, no employee is both a technician and an accoun
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14 Mar 2021, 21:43
14 Mar 2021, 21:43
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Carcass wrote:
In company X, no employee is both a technician and an accountant. Also, in company X, \(\frac{2}{5}\) of the employees are technicians, and \(\frac{5}{16}\) of the remaining employees are accountants. What fraction of the total number of employees at company X are neither technicians nor accountants?
A. \(\frac{23}{80}\)
B. \(\frac{33}{80}\)
C. \(\frac{3}{7}\)
D. \(\frac{47}{80}\)
E. \(\frac{57}{80}\)
A. \(\frac{23}{80}\)
B. \(\frac{33}{80}\)
C. \(\frac{3}{7}\)
D. \(\frac{47}{80}\)
E. \(\frac{57}{80}\)
We can see the denominators of given fractions are \(5\) and \(16\) - Let us assume the total number of employees as a multiple of their LCM i.e. \(80\)
Also, the option choices have \(80\) as the denominator!
Technicians = \(\frac{2}{5}(80) = 32\)
Remaining = \(80 - 32 = 48\)
Accountants = \(\frac{5}{16}(48) = 15\)
Neither technicians nor accountants = \(80 - 32 - 15 = 33\)
Required fraction = \(\frac{33}{80}\)
Hence, option B
