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GRE Prep Club Team Member
Joined: 20 Feb 2017
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If ab < 0, a > b, and a > −b, which of the following must be true?
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17 Mar 2021, 05:30
17 Mar 2021, 05:30
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If ab < 0, a > b, and a > −b, which of the following must be true?
(A) a/b > 0
(B) a + b < 0
(C) b − (−a) > 0
(D) a/b = 1
(E) a − b < 0
(A) a/b > 0
(B) a + b < 0
(C) b − (−a) > 0
(D) a/b = 1
(E) a − b < 0
Re: If ab < 0, a > b, and a > −b, which of the following must be true?
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17 Mar 2021, 08:21
17 Mar 2021, 08:21
ab < 0, a > b, and a > −b
a > −b
a + b > 0
Option C = b − (−a) > 0 = b + a > 0
Answer C
a > −b
a + b > 0
Option C = b − (−a) > 0 = b + a > 0
Answer C
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Re: If ab < 0, a > b, and a > −b, which of the following must be true?
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17 Mar 2021, 11:14
17 Mar 2021, 11:14
1
GeminiHeat wrote:
If ab < 0, a > b, and a > −b, which of the following must be true?
(A) a/b > 0
(B) a + b < 0
(C) b − (−a) > 0
(D) a/b = 1
(E) a − b < 0
(A) a/b > 0
(B) a + b < 0
(C) b − (−a) > 0
(D) a/b = 1
(E) a − b < 0
The answer lies in the 3rd inequality
\(a > -b\)
i.e. \(a + b > 0\)
We can go for option C
Alternatively:
\(ab < 0\)
So, wither \(a\) is +ve and \(b\) -ve OR \(a\) is -ve and \(b\) +ve
\(a > b\)
This means \(a\) cannot be -ve
So we stick to \(a\) is +ve and \(b\) -ve
\(a > -b\)
\(-b\) would be a +ve number and \(a\) is more +ve than it
Let us assume two number which satisfy all three inequalities
\(a = 3\) and \(b = -2\)
A. \(\frac{3}{-2} > 0\) - NO
B. 3 + (-2) < 0 - NO
C. (-2) - (-3) > 0 - YES
D. \(\frac{3}{-2} = 1\) - NO
E. (3) - (-2) < 0 - NO
