GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Pipe A usually fills a tank in 3 hours. Due to a leak, it takes pipe A
[#permalink]
Updated on: 04 Sep 2024, 02:32
Updated on: 04 Sep 2024, 02:32
1
1
9
Bookmarks
00:00
Question Stats:
48% (02:33) correct
51% (02:02) wrong based on 33 sessions
Hide Show timer Statistics
Pipe A usually fills a tank in 3 hours. Due to a leak, it takes pipe A 45 more minutes to fill the tank.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Number of hours required to empty the tank when pipe A is shut |
12 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Originally posted by KarunMendiratta on 18 Mar 2021, 03:03.
Last edited by Carcass on 04 Sep 2024, 02:32, edited 2 times in total.
Last edited by Carcass on 04 Sep 2024, 02:32, edited 2 times in total.
Formatted
Re: Pipe A usually fills a tank in 3 hours. Due to a leak, it takes pipe A
[#permalink]
18 Mar 2021, 19:32
18 Mar 2021, 19:32
2
3
Bookmarks
Pipe A fills the tank in 3 hrs
With leak, it takes 45 mins more so total time = 3\(\frac{3}{4}\)hrs = \(\frac{15}{4}\) hrs
Let's take the time it needs to empty the full tank = \(x\) hrs (when pipe A is shut)
\(\frac{1}{3}\) - \(\frac{1}{x}\) = \(\frac{4}{15}\)
\(\frac{1}{3}\) - \(\frac{4}{15}\) = \(\frac{1}{x}\)
x = 15 hrs
Qt A > Qt B
Answer A
With leak, it takes 45 mins more so total time = 3\(\frac{3}{4}\)hrs = \(\frac{15}{4}\) hrs
Let's take the time it needs to empty the full tank = \(x\) hrs (when pipe A is shut)
\(\frac{1}{3}\) - \(\frac{1}{x}\) = \(\frac{4}{15}\)
\(\frac{1}{3}\) - \(\frac{4}{15}\) = \(\frac{1}{x}\)
x = 15 hrs
Qt A > Qt B
Answer A
General Discussion
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: Pipe A usually fills a tank in 3 hours. Due to a leak, it takes pipe A
[#permalink]
20 Mar 2021, 04:41
20 Mar 2021, 04:41
1
KarunMendiratta wrote:
Pipe A usually fills a tank in 3 hours. Due to a leak, it takes pipe A 45 more minutes to fill the tank.
Quantity A |
Quantity B |
Number of hours required to empty the tank when pipe A is shut |
12 |
Explanation:
If A can do a job in \(X\) hours, while B can do it in \(Y\) hours, then they can both finish the job (working together) in \(\frac{XY}{(X+Y)}\)
Here,
Let the time required to empty the tank be X hours
\(3 + \frac{45}{60} = \frac{3X}{(X+3)}\)
\((3.75)(X+3) = 3X\)
\(3.75X + 11.25 = 3X\)
\(X = \frac{-11.25}{0.75} =-15\) hours
[-ve sign indicated that the work done is opposite - i.e. opposite to filling the tank]
Col. A: \(15\)
Col. B: \(12\)
Hence, option A
