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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1053
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How many terms are there in the sequence of consecutive integers from
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19 Mar 2021, 05:30
19 Mar 2021, 05:30
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Question Stats:
87% (00:29) correct
12% (00:41) wrong based on 8 sessions
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How many terms are there in the sequence of consecutive integers from −18 to 33, inclusive?
A. 44
B. 46
C. 48
D. 50
E. 52
A. 44
B. 46
C. 48
D. 50
E. 52
Re: How many terms are there in the sequence of consecutive integers from
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19 Mar 2021, 06:37
19 Mar 2021, 06:37
1
Solution:
There are
18 negative terms from -1 to -18
33 positive terms from 1 to 33
And a zero
Thus, 18+33+1=52
IMO E
Hope this helps
There are
18 negative terms from -1 to -18
33 positive terms from 1 to 33
And a zero
Thus, 18+33+1=52
IMO E
Hope this helps
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Re: How many terms are there in the sequence of consecutive integers from
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19 Mar 2021, 09:08
19 Mar 2021, 09:08
1
GeminiHeat wrote:
How many terms are there in the sequence of consecutive integers from −18 to 33, inclusive?
A. 44
B. 46
C. 48
D. 50
E. 52
A. 44
B. 46
C. 48
D. 50
E. 52
Inclusive terms between any given range is given by \(L - F + 1\)
Where, \(L\) is Last term, and \(F\) is First term
Here, n = \(33 - (-18) + 1 = 33 + 18 + 1 = 52\)
Hence, option E
