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The perimeters of Rand S are equal.
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08 Mar 2020, 10:44
08 Mar 2020, 10:44
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80% (00:55) correct
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The perimeters of R and S are equal.
Quantity A |
Quantity B |
The area of R |
The area of S |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
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Re: The perimeters of Rand S are equal.
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10 Mar 2020, 05:58
10 Mar 2020, 05:58
2
Carcass wrote:
Attachment:
#greprepclub The perimeters of R and S are equal. .jpg
The perimeters of Rand S are equal.
Quantity A |
Quantity B |
The area of R |
The area of S |
GIVEN: The perimeters of R and S are equal.
Perimeter of rectangle R = x + 2x + x + 2x = 6x
This means the perimeter of square S = 6x
So, the length of EACH SIDE of square S = 6x/4 = 1.5x
Area of rectangle R = (x)(2x) = 2x²
Area of square S = (1.5x)² = 2.25x²
We have:
QUANTITY A: 2x²
QUANTITY B: 2.25x²
At this point, if we aren't already convinced that quantity B is greater, we can also recognize that, since x² must be POSITIVE, we can safely divide both quantities by x² to get:
QUANTITY A: 2
QUANTITY B: 2.25
Answer: B
Cheers,
Brent
Re: The perimeters of Rand S are equal.
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23 Mar 2021, 09:26
23 Mar 2021, 09:26
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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