GeminiHeat wrote:
Triplets Adam, Bruce, and Charlie enter a triathlon. If there are 9 competitors in the triathlon, and medals are awarded for first, second, and third place, what is the probability that at least two of the triplets will win a medal?
A. 3/14
B. 19/84
C. 11/42
D. 15/28
E. 3/4
Total ways to distribute the medals = \(^9C_3 = 84\)
At-least two win a medal = any two win + all three win
\(= (^3C_2)(^6C_1) + (^3C_3)\)
\(= (3)(6) + 1\)
\(= 19\)
Required Probability = \(\frac{19}{84}\)
Hence, option B