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There are 750 male and female participants in a meeting. Hal
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03 May 2019, 02:11
03 May 2019, 02:11
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92% (02:00) correct
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There are 750 male and female participants in a meeting. Half the female participants and one-quarter of the male participants are Democrats. One-third of all the participants are Democrats. How many of the Democrats are female?
(A) 75
(B) 100
(C) 125
(D) 175
(E) 225
(A) 75
(B) 100
(C) 125
(D) 175
(E) 225
Re: There are 750 male and female participants in a meeting. Hal
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03 May 2019, 20:47
03 May 2019, 20:47
1
x/2+(750-x)/4=750/3, So, FemaleDemocrats =250/2=>125. C
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Re: There are 750 male and female participants in a meeting. Hal
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27 Mar 2021, 14:13
27 Mar 2021, 14:13
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Carcass wrote:
There are 750 male and female participants in a meeting. Half the female participants and one-quarter of the male participants are Democrats. One-third of all the participants are Democrats. How many of the Democrats are female?
(A) 75
(B) 100
(C) 125
(D) 175
(E) 225
(A) 75
(B) 100
(C) 125
(D) 175
(E) 225
There are 750 male and female participants in a meeting.
Let M = the number of males
Let F = the number of females
So, we can write: F + M = 750
One-third of all the participants are Democrats.
1/3 of 750 = 250
So, there are 250 Democrats in TOTAL
Half the female participants and one-quarter of the male participants are Democrats
(# of female Democrats) + (# of male Democrats) = TOTAL number of Democrats
So, we can write: (1/2)F + (1/4)M = 250
To eliminate the fractions, let's multiply both sides by 4 to get: 2F + M = 1000
How many of the Democrats are female?
We already know:
2F + M = 1000
F + M = 750
Subtract the bottom equation from the top equation to get: F = 250
So, there are 250 females, and we're told that 1/2 of them are Democrats
1/2 of 250 = 125
Answer: C
Cheers,
Brent
