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The youngest of 4 children has siblings who are 3, 5, and 8 years olde
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31 Mar 2021, 05:31
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The youngest of 4 children has siblings who are 3, 5, and 8 years older than she is. If the average (arithmetic mean) age of the 4 siblings is 21, what is the age of the youngest sibling?
Re: The youngest of 4 children has siblings who are 3, 5, and 8 years olde
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31 Mar 2021, 05:45
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Carcass wrote:
The youngest of 4 children has siblings who are 3, 5, and 8 years older than she is. If the average (arithmetic mean) age of the 4 siblings is 21, what is the age of the youngest sibling?
So, y + 3 = age of sibling who is 3 years older than the youngest child y + 5 = age of sibling who is 5 years older than the youngest child y + 8 = age of sibling who is 8 years older than the youngest child
The average (arithmetic mean) age of the 4 siblings is 21 This means: [y + (y+3) + (y+5) + (y+8)]/4 = 21 Multiply both sides by 4 to get: y + (y+3) + (y+5) + (y+8) = 84 Simplify: 4y + 16 = 84 Solve: y = 17
The youngest of 4 children has siblings who are 3, 5, and 8 years olde
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31 Mar 2021, 06:37
Carcass wrote:
The youngest of 4 children has siblings who are 3, 5, and 8 years older than she is. If the average (arithmetic mean) age of the 4 siblings is 21, what is the age of the youngest sibling?
A. 17 B. 18 C. 19 D. 21 E. 22
Let the age of the youngest sibling be \(x\) Age of other siblings = \(x+3\), \(x+5\), and \(x+8\)