Carcass wrote:
Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.80 at the candy store. What is John’s weekly allowance?
A. $2.40
B. $3.00
C. $3.20
D. $3.60
E. $4.80
Let his weekly allowance be \(x\)
1st day he spent = \(\frac{3x}{5}\)
Left over = \(x - \frac{3x}{5} = \frac{2x}{5}\)
2nd day he spent = \(\frac{1}{3}(\frac{2x}{5}) = \frac{2x}{15}\)
Left over = \(\frac{2x}{5} - \frac{2x}{15} = \frac{4x}{15}\)
Given, \(\frac{4x}{15} = 0.80\)
\(4x = 12\)
\(x = 3\)
Hence, option B