Carcass wrote:
The digits of a three-digit number add up to 18. If the ten’s digit is twice the hundred’s digit and the hundred’s digit is 1/3 the unit’s digit, what is the number?
(A) 246
(B) 369
(C) 531
(D) 855
(E) 893
Alternate Approach:Let us assume the number to be \(abc\)
Given, \(a + b + c = 18\) and \(b = 2a\), \(a = \frac{c}{3}\)
i.e. \(a + 2a + 3a = 18\)
\(6a = 18\)
\(a = 3\)
The only number starting with \(3\) is option B
Else, we can see that the number would be \(369\)