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What is the largest integer if the sum of three consecutive even integ
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02 Apr 2021, 05:04
02 Apr 2021, 05:04
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Question Stats:
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What is the largest integer if the sum of three consecutive even integers is 318?
A. 100
B. 104
C. 106
D. 108
E. 111
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 100
B. 104
C. 106
D. 108
E. 111
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Posts: 6218
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Re: What is the largest integer if the sum of three consecutive even integ
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02 Apr 2021, 05:06
02 Apr 2021, 05:06
1
Carcass wrote:
What is the largest integer if the sum of three consecutive even integers is 318?
A. 100
B. 104
C. 106
D. 108
E. 111
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 100
B. 104
C. 106
D. 108
E. 111
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Let x = the smallest value
So, x + 2 = the middle value
And x + 4 = the biggest value
The sum is 318
So, we can write x + (x+2) + (x+4) = 318
Simplify: 3x + 6 = 318
Subtract 6 from both sides to get: 3x = 312
Solve: x = 104
So, the SMALLEST value = 104
This means 106 is the MIDDLE value and 108 is the BIGGEST value
Answer: D
Cheers,
Brent
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: What is the largest integer if the sum of three consecutive even integ
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02 Apr 2021, 05:56
02 Apr 2021, 05:56
Carcass wrote:
What is the largest integer if the sum of three consecutive even integers is 318?
A. 100
B. 104
C. 106
D. 108
E. 111
A. 100
B. 104
C. 106
D. 108
E. 111
Three consecutive even integers are \((x - 2), x, (x + 2)\)
Given, \((x - 2) + x + (x + 2) = 318\)
\(3x = 318\)
\(x = 106\)
Largest integer \(= x + 2 = 108\)
Hence, option D
