KarunMendiratta wrote:
f(x)=ax2+bx+c
The equation above represents a parabola in the xy-plane. If a<0 and the x-intercepts of the parabola are −1 and 3, which of the following could be the vertex of the parabola?
A. (2,5)
B. (1,−3)
C. (2,3)
D. (1,4)
E. (2,−2)
Explanation:The vertex of Parabola lies at the mid-point of x-intercepts (or x values for which we have same y values)
Here,
xv=3+(−1)2=1Eliminate A, C, and E
Since,
a<0, the Parabola will open downwards with the y-coordinate of vertex (Maximum point in this case) as a +ve value
Hence, option D