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M / P > N / P
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Updated on: 19 Feb 2017, 11:01
Updated on: 19 Feb 2017, 11:01
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Question Stats:
51% (00:35) correct
48% (00:30) wrong based on 29 sessions
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\(\frac{M}{P} > \frac{N}{P}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Hi All,
I found this question in Manhattan book but I am not confident regarding the solution provided. This is how I solved this question.
Algebraic Solution:
Since M / P > N / P
Step 1: M / P - N/P > 0
Step 2: M - N / P > 0
Step 3: M - N > 0 (Multiplying P with 0 - doesn't matter if p is positive or negative since it is being multiplied with 0 and the end product will be 0 anyways)
Step 4: M > N
So as per my solution, Quantity A is greater than Quantity B. However, as per Manhattan, the original answer is D. Their solution is " Without knowing the signs of any of the variables, you cannot assume that m is larger. While it certainly could be (for instance, m = 4, n = 2, and p = 1), if p is negative, the reverse will be true (for instance, m = 2, n = 4, and p = -1)"
I don't know how my solution is not correct. Any comments?
I appreciate your feedback!
Regards,
H.
Quantity A |
Quantity B |
M |
N |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Hi All,
I found this question in Manhattan book but I am not confident regarding the solution provided. This is how I solved this question.
Algebraic Solution:
Since M / P > N / P
Step 1: M / P - N/P > 0
Step 2: M - N / P > 0
Step 3: M - N > 0 (Multiplying P with 0 - doesn't matter if p is positive or negative since it is being multiplied with 0 and the end product will be 0 anyways)
Step 4: M > N
So as per my solution, Quantity A is greater than Quantity B. However, as per Manhattan, the original answer is D. Their solution is " Without knowing the signs of any of the variables, you cannot assume that m is larger. While it certainly could be (for instance, m = 4, n = 2, and p = 1), if p is negative, the reverse will be true (for instance, m = 2, n = 4, and p = -1)"
I don't know how my solution is not correct. Any comments?
I appreciate your feedback!
Regards,
H.
Originally posted by HarveyKlaus on 18 Feb 2017, 08:41.
Last edited by Carcass on 19 Feb 2017, 11:01, edited 1 time in total.
Last edited by Carcass on 19 Feb 2017, 11:01, edited 1 time in total.
Edited by Carcass
Re: M / P > N / P
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18 Feb 2017, 09:35
18 Feb 2017, 09:35
1
Expert Reply
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Hey,
Yes step 3 is wrong. Multiplying matters even if with 0
For example
-5 < 0
multiply -1 both side
If what you did in step 3 is correct.
5 < 0.
Which is well not correct.
So D is indeed the right answer.
Yes step 3 is wrong. Multiplying matters even if with 0
For example
-5 < 0
multiply -1 both side
If what you did in step 3 is correct.
5 < 0.
Which is well not correct.
So D is indeed the right answer.
