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The price of the item in January 2007 was k, which is a 15% increase
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08 Apr 2021, 20:12
08 Apr 2021, 20:12
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Question Stats:
70% (01:08) correct
29% (00:56) wrong based on 41 sessions
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The price of the item in January 2007 was \(K\), which is a 15% increase from the price of the same item in January 2006.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Price of the item in January 2006 |
\(0.85K\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
The price of the item in January 2007 was k, which is a 15% increase
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09 Apr 2021, 02:37
09 Apr 2021, 02:37
Quote:
K, which is a 15% increase from the price of the same item in January 2006
If price of the item in Jan 2006 is S, then K = 1.15 S
We have to compare S and 0.85K.
Therefore, let's convert S into K.
\(S = \frac{K}{1.15}\)
\(S = K * \frac{100 }{ 115} \)
\(S = K * \frac{20 }{ 23}\)
\(0.85 * K = \frac{85 }{ 100} * K = \frac{17 }{ 20 }* K\)
To compare fractions \(\frac{20}{23}, and \frac{17 }{ 20}\), cross-multiply.
\(20 * 20 > 17 * 20\)
So, \(\frac{20 }{ 23} * K > \frac{17 }{ 20} * K\)
or S > 0.85 K
Hence, A is the correct answer.
Re: The price of the item in January 2007 was k, which is a 15% increase
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09 Apr 2021, 23:10
09 Apr 2021, 23:10
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Let the price in 2006 be 100
So, the price in 2007 will 15/100*100 = 15
100+15= 115
So K will be 115
Quantity A = 100
Quantity B = 0.85K
0.85*115= 97.75
Hence Quantity A > Quantity B
So, the price in 2007 will 15/100*100 = 15
100+15= 115
So K will be 115
Quantity A = 100
Quantity B = 0.85K
0.85*115= 97.75
Hence Quantity A > Quantity B
