GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The decimal r = 2.666666 continues forever in that repeating
[#permalink]
Updated on: 20 Feb 2017, 10:04
Updated on: 20 Feb 2017, 10:04
2
13
Bookmarks
00:00
Question Stats:
76% (01:34) correct
23% (01:00) wrong based on 172 sessions
Hide Show timer Statistics
The decimal r = 2.666666 continues forever in that repeating decimal pattern. When written as a fraction in lowest terms, r = a/b, where a and b are positive numbers.
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
Quantity A |
Quantity B |
a + b |
10 |
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
Originally posted by leonidbasin1 on 19 Feb 2017, 21:55.
Last edited by Carcass on 20 Feb 2017, 10:04, edited 1 time in total.
Last edited by Carcass on 20 Feb 2017, 10:04, edited 1 time in total.
Edited by Carcass
Re: The decimal r = 2.666666 continues forever in that repeating
[#permalink]
20 Feb 2017, 05:04
20 Feb 2017, 05:04
10
Expert Reply
3
Bookmarks
Explanation
We have r = 2.666666......
So 10r = 26.666666....
We can write \(10r - r = 26.66666... - 2.666666.. = 24\)
So \(9r = 24\) or \(r =\frac{24}{9}=\frac{8}{3}\).
Hence a= 8 and b = 3. Thus \(a+b = 11\)
Hence clearly Quantity A is greater.
Alternatively you can remember .666666 .... is actually \(\frac{2}{3}\). So \(2.6666....\) is \(2\frac{2}{3}\).
The method above would work with any number of repeating decimals.
We have r = 2.666666......
So 10r = 26.666666....
We can write \(10r - r = 26.66666... - 2.666666.. = 24\)
So \(9r = 24\) or \(r =\frac{24}{9}=\frac{8}{3}\).
Hence a= 8 and b = 3. Thus \(a+b = 11\)
Hence clearly Quantity A is greater.
Alternatively you can remember .666666 .... is actually \(\frac{2}{3}\). So \(2.6666....\) is \(2\frac{2}{3}\).
The method above would work with any number of repeating decimals.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: The decimal r = 2.666666 continues forever in that repeating
[#permalink]
26 May 2018, 10:16
26 May 2018, 10:16
6
leonidbasin1 wrote:
The decimal r = 2.666666 continues forever in that repeating decimal pattern. When written as a fraction in lowest terms, r = a/b, where a and b are positive numbers.
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
Quantity A |
Quantity B |
a + b |
10 |
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
Given: r = 2.666666....
We know that 2/3 = 666666....
So, 2.666666.... = 2 + 2/3
Let's combine 2 + 2/3 into ONE fraction
2 + 2/3 = 6/3 + 2/3 = 8/3
Since the fraction 8/3 is in lowest terms, we can say that r = 2.666666... = 8/3 = a/b
So, a = 8 and b = 3
We get:
Quantity A: 8 + 3
Quantity B: 10
Evaluate:
Quantity A: 11
Quantity B: 10
Answer: A
Cheers,
Brent
