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m is defined as the largest integer
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15 Apr 2021, 03:53
15 Apr 2021, 03:53
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\(m\) is defined as the largest integer that is smaller than 12.022
\(n\) is defined as the smallest integer that is greater than 23.032
\(p\) is defined as the middle integer of the integers that lie between 34.43 and 43.34
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
\(n\) is defined as the smallest integer that is greater than 23.032
\(p\) is defined as the middle integer of the integers that lie between 34.43 and 43.34
Quantity A |
Quantity B |
\(m^{n+p}\) |
\(n^{m+p}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
m is defined as the largest integer
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15 Apr 2021, 07:25
15 Apr 2021, 07:25
\(m\) is defined as the largest integer that is smaller than 12.022 - So \(m\) will be \(12\)
\(n\) is defined as the smallest integer that is greater than 23.032 - \(n\) will be \(24\)
\(p\) is defined as the middle integer of the integers that lie between 34.43 and 43.34 -
Nos are 35 36 37 38 39 40 41 42 43 - middle no \(p\) will be \(39\)
Qt A \(m^{n+p}\)
\(12^{24+39}\) = \(12^{63}\) = \(3^{63} * 2^{126}\)
Qt B \(n^{m+p}\)
\(24^{12+39}\) = \(24^{51}\) = \(2^{153} * 3^{51}\)
divide both the sides with \(2^{126} * 3^{51}\)
Qt A = \(3^{12}\) & Qt B = \(2^{27}\)
Qt B > QT A
Answer B
\(n\) is defined as the smallest integer that is greater than 23.032 - \(n\) will be \(24\)
\(p\) is defined as the middle integer of the integers that lie between 34.43 and 43.34 -
Nos are 35 36 37 38 39 40 41 42 43 - middle no \(p\) will be \(39\)
Qt A \(m^{n+p}\)
\(12^{24+39}\) = \(12^{63}\) = \(3^{63} * 2^{126}\)
Qt B \(n^{m+p}\)
\(24^{12+39}\) = \(24^{51}\) = \(2^{153} * 3^{51}\)
divide both the sides with \(2^{126} * 3^{51}\)
Qt A = \(3^{12}\) & Qt B = \(2^{27}\)
Qt B > QT A
Answer B
Re: m is defined as the largest integer
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13 Mar 2023, 01:37
13 Mar 2023, 01:37
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
