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Re: A moving cargo [#permalink]
1
toantoantoan wrote:
\(\frac{1}{12}\)*(x-15)=\(\frac{5}{4}\)

x=30

B


If the train and polar bear are moving in the opposite directions, the relative speed should be = X + 15, assuming X is the speed of the train.
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Re: A moving cargo [#permalink]
nurakib wrote:
toantoantoan wrote:
\(\frac{1}{12}\)*(x-15)=\(\frac{5}{4}\)

x=30

B


If the train and polar bear are moving in the opposite directions, the relative speed should be = X + 15, assuming X is the speed of the train.


they are facing each other or not? or they are facing in same direction?
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Re: A moving cargo [#permalink]
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