This one is very time consuming.

$245000 invested at 3.5% compounded annually for 3 years.
So the total sum \(= 245000(1.035)^3 = 271635.88\)

Then $50000 is added so new sum invested will be \(271635.88 + 50000 = 321635.88\)

Now for next 17 years at 5.5% compounded annually

Total sum \(= 321635.88(1.055)^{17}\) = 799201.53

Now we are asked that if the investment initially is 125000 and for 5years no amount is added then after 20 years to get the same amount 799201.53, how much is needed to add each month after 5 years for 15 years. with the same %rates

So for first 3 years at 3.5% rates
The sum \(= 125000(1.035)^3 = 138589.73\)

for next 2 years at 5.5% rates
The sum \(= 138589.73(1.055)^2 = 154253.83\)

Now we need the sum 799201.53 in the next 15 years.
So the shortage is \(= 799201.53 - 154253.83 = 644947.7\)

Let the amount = \(p\)

\(644947.7 = p (1.055)^{15}\)

\(p = 288902.97\)

Now this is for 15 years but each year same amount was added.

Amount added each year \(= \frac{288902.97}{15} = 19260.19\)

Answer B

P.S. - I am not sure the method is correct but surely recommend to skip this if comes in the exam.