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Which of the following is true for y=1/x-1/x+1
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21 Apr 2021, 05:13
21 Apr 2021, 05:13
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73% (00:52) correct
26% (01:03) wrong based on 19 sessions
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Which of the following is true for \(y=\frac{1}{x}-\frac{1}{x+1}\)?
Select all that apply
A. \(y=\frac{1}{x(x+1)}\)
B. \(y=\frac{\frac{1}{x}}{x+1}
\)
C. \(y=\frac{\frac{1}{x^2}}{\frac{x+1}{x}}
\)
D. \(y=\frac{x}{x+1}\)
E. \(y=\frac{x}{x-2}\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Select all that apply
A. \(y=\frac{1}{x(x+1)}\)
B. \(y=\frac{\frac{1}{x}}{x+1}
\)
C. \(y=\frac{\frac{1}{x^2}}{\frac{x+1}{x}}
\)
D. \(y=\frac{x}{x+1}\)
E. \(y=\frac{x}{x-2}\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Which of the following is true for y=1/x-1/x+1
[#permalink]
21 Apr 2021, 07:42
21 Apr 2021, 07:42
1
\(y=\frac{1}{x}-\frac{1}{x+1}\)
= \(\frac{x+1 - x}{x(x+1)}\)
= \(\frac{1}{x(x+1)}\) = \(\frac{\frac{1}{x}}{x+1}\) = \(\frac{\frac{1}{x^2}}{\frac{x+1}{x}}\)
Answer A B C
= \(\frac{x+1 - x}{x(x+1)}\)
= \(\frac{1}{x(x+1)}\) = \(\frac{\frac{1}{x}}{x+1}\) = \(\frac{\frac{1}{x^2}}{\frac{x+1}{x}}\)
Answer A B C
gmatclubot
Which of the following is true for y=1/x-1/x+1 [#permalink]
21 Apr 2021, 07:42
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