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36% (02:17) correct 63% (02:06) wrong based on 38 sessionsAs we have |x-1| in the equation so we will have two cases | |
-Case 1: x - 1 ≥ 0 => x ≥ 1 => | x-1 | = x-1 => x-1 = 3x + 3 (From (1)) => 2x = -4 => x = -2 But our condition was x ≥ 1 => NO SOLUTION | -Case 2: x ≤ 1 => | x-1 | = -(x-1) => -(x-1) = 3x + 3 (From (1)) => -x + 1 = 3x + 3 => 4x = -2 => x = -2/4 = -0.5 But our condition was x ≤ 1, and -0.5 ≤ 1 => x = -0.5 is a SOLUTION |
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