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-5x+12y=18
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29 Apr 2021, 10:48
29 Apr 2021, 10:48
Expert Reply
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Question Stats:
78% (01:54) correct
21% (02:17) wrong based on 32 sessions
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\(-5x+12y=18\)
\(2x-6y=-11\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
\(2x-6y=-11\)
Quantity A |
Quantity B |
The value of the product of x and y |
The value of the sum of x and y |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
-5x+12y=18
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30 Apr 2021, 05:57
30 Apr 2021, 05:57
By multiplying 2nd equation by 2.
\(4x-12y = -22\)
By adding this with 1st equation, we get
\(-x = -4 \)
\(x = 4\)
Putting the value of x in 1st equation
\(y = 4\)
\(x*y = 16\)
\(x+y = 8 \)
Hence, A
\(4x-12y = -22\)
By adding this with 1st equation, we get
\(-x = -4 \)
\(x = 4\)
Putting the value of x in 1st equation
\(y = 4\)
\(x*y = 16\)
\(x+y = 8 \)
Hence, A
Re: -5x+12y=18
[#permalink]
11 Mar 2022, 05:11
11 Mar 2022, 05:11
2
tapas3016 wrote:
By multiplying 2nd equation by 2.
\(4x-12y = -22\)
By adding this with 1st equation, we get
\(-x = -4 \)
\(x = 4\)
Putting the value of x in 1st equation
\(y = 4\)
\(x*y = 16\)
\(x+y = 8 \)
Hence, A
\(4x-12y = -22\)
By adding this with 1st equation, we get
\(-x = -4 \)
\(x = 4\)
Putting the value of x in 1st equation
\(y = 4\)
\(x*y = 16\)
\(x+y = 8 \)
Hence, A
How is Y= 4?
12Y - 5X = 18
12y -20 = 18
12Y = 38
Y= 38/12 (it's not 48 by 4)
thats 3.166
4 + 3.166 = 7.166
4*3.666 > 12
A>B
