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$620 is to be divided among three brothers A,B, and C so that A gets
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26 Apr 2021, 12:37
26 Apr 2021, 12:37
Expert Reply
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Question Stats:
16% (01:59) correct
83% (02:53) wrong based on 12 sessions
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$620 is to be divided among three brothers A,B, and C so that A gets 2/3 of what B gets and B gets 2/5 of what C gets. What is the approximation amount A,B,and C will each get?
Select all that apply
A. $86
B. $168
C. $213
D. $283
E. $321
F. $366
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Select all that apply
A. $86
B. $168
C. $213
D. $283
E. $321
F. $366
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Re: $620 is to be divided among three brothers A,B, and C so that A gets
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30 Apr 2021, 00:28
30 Apr 2021, 00:28
3
Total $620
Let's say C gets \(15x\), \(B = 6x\) & \(A = 4x\)
Total \(25 x = 620\)
By solving and putting the value of \(x\) in the shares of each,
\(C = 372 , B = 149 , A = 99\)
None among the options
Let's say C gets \(15x\), \(B = 6x\) & \(A = 4x\)
Total \(25 x = 620\)
By solving and putting the value of \(x\) in the shares of each,
\(C = 372 , B = 149 , A = 99\)
None among the options
$620 is to be divided among three brothers A,B, and C so that A gets
[#permalink]
30 Apr 2021, 09:21
30 Apr 2021, 09:21
2
Expert Reply
Official Explanation
Let C be \(x\) then B will be \(\frac{2x}{3}\) and A will be \(\frac{4x}{15}\).
So, \(\frac{4x}{15}+\frac{2x}{3}+x=620x=320.7
\)
The share of A will be \(4 \times \frac{320.7}{15}=86\)
B will be \(2 \times \frac{320.7}{3}=213
\)
C will be 321
Let C be \(x\) then B will be \(\frac{2x}{3}\) and A will be \(\frac{4x}{15}\).
So, \(\frac{4x}{15}+\frac{2x}{3}+x=620x=320.7
\)
The share of A will be \(4 \times \frac{320.7}{15}=86\)
B will be \(2 \times \frac{320.7}{3}=213
\)
C will be 321
