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The figure above shows a semicircle with center O and a quar [#permalink]
Area of shaded region = π \((6)^2\)/4
= \(9π \)

Area of Semi circle =π \((4)^2\)/2
= \(8π \)

Dividing 1st by 2nd

9/8. Hence, E
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The figure above shows a semicircle with center O and a quar [#permalink]
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