rx10 wrote:
This is a very nice question.
x=1010−z & z - two digit integer
Now 103− any two digit no = 9ab
104−any two digit no = 99ab
Similarly
1010− any two digit no = 99999999ab
It's given that the sum of digits of x = 84
We already have 8times 9 = 72
So sum of ab=12
So we need ab in which the sum of the digits = 12
39,48,57,66,75,84,93
Now if we put ab = 93 , z will be 7 , but z is a two digit integer
So total 6 nos.
Answer D
Can you explain this part again: Now 103−
10
3
−
any two digit no = 9ab
9
a
b
104−
10
4
−
any two digit no = 99ab
99
a
b
Similarly
1010−
10
10
−
any two digit no = 99999999ab