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(1/5)^(−1)(1/3)^8−(1/4)^(−1)(1/3)^6(1/9)
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04 May 2021, 22:03
04 May 2021, 22:03
Expert Reply
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Question Stats:
83% (01:17) correct
16% (00:32) wrong based on 12 sessions
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\((\frac{1}{5})^{(−1)}(\frac{1}{3})^8−(\frac{1}{4})^{(−1)}(\frac{1}{3})^6(\frac{1}{9})= \)
A. \((\frac{1}{3})^{−8}\)
B. \((\frac{1}{3})^6\)
C. \((\frac{1}{3})^9\)
D. \(9^{−6}\)
E. \(9^{−4}\)
A. \((\frac{1}{3})^{−8}\)
B. \((\frac{1}{3})^6\)
C. \((\frac{1}{3})^9\)
D. \(9^{−6}\)
E. \(9^{−4}\)
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Re: (1/5)^(−1)(1/3)^8−(1/4)^(−1)(1/3)^6(1/9)
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05 May 2021, 10:43
05 May 2021, 10:43
1
GeminiHeat wrote:
\((\frac{1}{5})^{(−1)}(\frac{1}{3})^8−(\frac{1}{4})^{(−1)}(\frac{1}{3})^6(\frac{1}{9})= \)
A. \((\frac{1}{3})^{−8}\)
B. \((\frac{1}{3})^6\)
C. \((\frac{1}{3})^9\)
D. \(9^{−6}\)
E. \(9^{−4}\)
A. \((\frac{1}{3})^{−8}\)
B. \((\frac{1}{3})^6\)
C. \((\frac{1}{3})^9\)
D. \(9^{−6}\)
E. \(9^{−4}\)
\((\frac{1}{5})^{(−1)}(\frac{1}{3})^8−(\frac{1}{4})^{(−1)}(\frac{1}{3})^6(\frac{1}{9})\)
\(\frac{5}{3^8} - \frac{4}{3^8}\)
\(\frac{1}{3^8} (5 - 4) = \frac{1}{3^8}\)
Hence, option E
General Discussion
Re: (1/5)^(−1)(1/3)^8−(1/4)^(−1)(1/3)^6(1/9)
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30 Aug 2021, 03:24
30 Aug 2021, 03:24
The question stem needs to be more clear here . If it is (1/5) ^ -1 , or if its is (1/5) * -1 .
You get the right ans only when u consider the former case as the later case is not applicable
You get the right ans only when u consider the former case as the later case is not applicable
