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The circumference of a circle is
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06 May 2021, 05:12
06 May 2021, 05:12
Expert Reply
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Question Stats:
92% (00:43) correct
7% (01:12) wrong based on 28 sessions
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The circumference of a circle is \(2\pi^2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
The area of the circle |
27 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
The circumference of a circle is
[#permalink]
06 May 2021, 08:20
06 May 2021, 08:20
1
Circumference of the circle = \(2πr\)
\(2πr\) = 2\(π^2\)
By solving
r = \(π\)
Quantity A = \(π\)*\(π^2\) = \(π^3\) = \((3.14)^3\) > 27
Quantity B = 27
Hence, A
\(2πr\) = 2\(π^2\)
By solving
r = \(π\)
Quantity A = \(π\)*\(π^2\) = \(π^3\) = \((3.14)^3\) > 27
Quantity B = 27
Hence, A
Re: The circumference of a circle is
[#permalink]
06 May 2021, 08:25
06 May 2021, 08:25
1
Solution:
Deconstructing the question we get:
Circumference of the circle=2πr
\(2π^2\)=2πr
r=π
Thus, Area of the circle=\(πr^2\)
=\(π^3\)
Thus, Area=\(3.14^3\)~31
Qty A: 31
Qty B: 27
A>B
IMO A
Hope this helps!
Deconstructing the question we get:
Circumference of the circle=2πr
\(2π^2\)=2πr
r=π
Thus, Area of the circle=\(πr^2\)
=\(π^3\)
Thus, Area=\(3.14^3\)~31
Qty A: 31
Qty B: 27
A>B
IMO A
Hope this helps!
