GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The circumference of a circle is
[#permalink]
06 May 2021, 05:12
06 May 2021, 05:12
Expert Reply
00:00
Question Stats:
93% (00:40) correct
6% (01:12) wrong based on 33 sessions
Hide Show timer Statistics
The circumference of a circle is \(2\pi^2\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
The area of the circle |
27 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
The circumference of a circle is
[#permalink]
06 May 2021, 08:20
06 May 2021, 08:20
1
Circumference of the circle = \(2πr\)
\(2πr\) = 2\(π^2\)
By solving
r = \(π\)
Quantity A = \(π\)*\(π^2\) = \(π^3\) = \((3.14)^3\) > 27
Quantity B = 27
Hence, A
\(2πr\) = 2\(π^2\)
By solving
r = \(π\)
Quantity A = \(π\)*\(π^2\) = \(π^3\) = \((3.14)^3\) > 27
Quantity B = 27
Hence, A
Re: The circumference of a circle is
[#permalink]
06 May 2021, 08:25
06 May 2021, 08:25
1
Solution:
Deconstructing the question we get:
Circumference of the circle=2πr
\(2π^2\)=2πr
r=π
Thus, Area of the circle=\(πr^2\)
=\(π^3\)
Thus, Area=\(3.14^3\)~31
Qty A: 31
Qty B: 27
A>B
IMO A
Hope this helps!
Deconstructing the question we get:
Circumference of the circle=2πr
\(2π^2\)=2πr
r=π
Thus, Area of the circle=\(πr^2\)
=\(π^3\)
Thus, Area=\(3.14^3\)~31
Qty A: 31
Qty B: 27
A>B
IMO A
Hope this helps!
