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14, 23, 32, 41, 50, 59, … In the sequence above, each term is 9 more [#permalink]
1
Theory: Arithmetic Sequence: A sequence of numbers such that the difference between the consecutive term is constant

\(n^{th}\) term of an Arithmetic sequence is given by \(T{_n}\) = a + (n-1)*d
where, a is the first term
n is number of terms or term number
d is the common difference (Difference between consecutive terms)

Given series is 14, 23, 32, 41, 50, 59, …
=> First term, a = 14
Common difference, d = 9 (difference between consecutive terms)
n = 41

Using, \(T{_n}\) = a + (n-1)*d. We get
\(T{_41}\) = 14 + (41-1)*9 = 14 + 40*9 = 14 + 360 = 374

So, Answer will be D
Hope it helps!

To Learn More about Arithmetic or Geometric Sequence watch the following video

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14, 23, 32, 41, 50, 59, … In the sequence above, each term is 9 more [#permalink]
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