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If m-n=1, where m
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29 Apr 2021, 10:41
29 Apr 2021, 10:41
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Question Stats:
58% (02:35) correct
41% (02:14) wrong based on 43 sessions
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If \(m-n=1\), where \(m \neq -n \neq 0\) , which of the following must be true ?
A. \(m(m-1)=n(n+1)\)
B. \(m(m+1)=n(n-1)\)
C. \(n(m+1)=m(n-1)\)
D. \(n(m-1)=m(n+1)\)
E. \(m(m+n)=n(m-n)\)
F. \(\frac{1}{mn^2}-\frac{1}{m^2n}+1=\frac{1+m^2n^2}{m^2n^2}\)
G. \(\frac{1}{mn^2}-\frac{1}{m^2n}+1=\frac{1+mn}{mn}\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. \(m(m-1)=n(n+1)\)
B. \(m(m+1)=n(n-1)\)
C. \(n(m+1)=m(n-1)\)
D. \(n(m-1)=m(n+1)\)
E. \(m(m+n)=n(m-n)\)
F. \(\frac{1}{mn^2}-\frac{1}{m^2n}+1=\frac{1+m^2n^2}{m^2n^2}\)
G. \(\frac{1}{mn^2}-\frac{1}{m^2n}+1=\frac{1+mn}{mn}\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Re: If m-n=1, where m
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01 May 2021, 02:55
01 May 2021, 02:55
1
In this kind of question, guess the values according to the conditions given.
For this que;
\(m-n=1\), where \(m \neq -n \neq 0\)
So take \(m = 2\) & \(n = 1\)
By putting these values in the given options,
For choice A & F only LHS = RHS
Answer \(A F\)
For this que;
\(m-n=1\), where \(m \neq -n \neq 0\)
So take \(m = 2\) & \(n = 1\)
By putting these values in the given options,
For choice A & F only LHS = RHS
Answer \(A F\)
Re: If m-n=1, where m
[#permalink]
10 May 2021, 10:56
10 May 2021, 10:56
do u think this kind a question comes in gre? how much time u took to solve this?
