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m>0,n>0,k>0
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14 May 2021, 10:08
14 May 2021, 10:08
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\(m>0,n>0,k>0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(m + \frac{1}{n+\frac{1}{k}}\) |
\(\frac{mnk++m+k}{nk+1 }\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: m>0,n>0,k>0
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14 May 2021, 22:56
14 May 2021, 22:56
1
Carcass wrote:
\(m>0,n>0,k>0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(m + \frac{1}{n+\frac{1}{k}}\) |
\(\frac{mnk+m+k}{nk+1 }\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Col. A: \(m + \frac{1}{n+\frac{1}{k}}\)
Col. B: \(\frac{mnk+m+k}{nk+1 }\)
Col. A: \(m + \frac{1}{\frac{nk+1}{k}}\)
Col. B: \(\frac{mnk+m+k}{nk+1 }\)
Col. A: \(m + \frac{k}{nk+1}\)
Col. B: \(\frac{mnk+m+k}{nk+1 }\)
Col. A: \(\frac{mnk+m+k}{nk+1 }\)
Col. B: \(\frac{mnk+m+k}{nk+1 }\)
Hence, option C
Re: m>0,n>0,k>0
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13 Jun 2022, 16:18
13 Jun 2022, 16:18
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